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In other words, when the compiler starts building your code, no #define statements or anything like that is left Array format for #define (c preprocessor) asked 13 years, 1 month ago modified 4 years, 7 months ago viewed 96k times A good way to understand what the preprocessor does to your code is to get hold of the preprocessed output and look at it.
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As far as i know, what you're trying to do (use if statement and then return a value from a macro) isn't possible in iso c.but it is somewhat possible with statement expressions (gnu extension) Asked 13 years, 8 months ago modified 1 year, 4 months ago viewed 1.2m times I've found that this works on gcc and clang by default:
The #define directive is a preprocessor directive
The preprocessor replaces those macros by their body before the compiler even sees it Think of it as an automatic search and replace of your source code A const variable declaration declares an actual variable in the language, which you can use.well, like a real variable Take its address, pass it around, use it, cast/convert it, etc
0 in c or c++ #define allows you to create preprocessor macros In the normal c or c++ build process the first thing that happens is that the preprocessor runs, the preprocessor looks though the source files for preprocessor directives like #define or #include and then performs simple operations with them. I want to write reusable code and need to declare some variables at the beginning and reuse them in the script, such as #define simply substitutes a name with its value
Furthermore, a #define 'd constant may be used in the preprocessor
You can use it with #ifdef to do conditional compilation based on its value, or use the stringizing operator # to get a string with its value. Is it better to use static const variables than #define preprocessor Or does it maybe depend on the context What are advantages/disadvantages for each method?
How do i define a function with optional arguments
